Re: How to list all files that are going to be installed when doing "apt-get upgrade"?
From: Sonixxfx (sonixxfx_at_gmail.com)
Date: 09/30/05
- Previous message: Andy Streich: "Re: 500 million Linux laptops in next year"
- In reply to: Joe Smith: "Re: How to list all files that are going to be installed when doing "apt-get upgrade"?"
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Date: Fri, 30 Sep 2005 07:21:45 +0200 To: debian-user@lists.debian.org
Thanks Joe,
It works quite well, only "awk '{print $1}'" also shows the "/unknown" part
that is appended to the packages names. For example:
libsnmp5/unknown
unzip/unknown
cpio/unknown
Because of this dpkg cannot handle this.
Can you tell me how I can exclude that "/unknown" part?
Thanks a lot
Regards,
Ben
On 9/29/05, Joe Smith <unknown_kev_cat@hotmail.com> wrote:
>
> >I know how to list the packages that are going to be installed, like with
> >"apt-get -s upgrade" or "apt-show-versions -u", but I >would like to know
> >which files included in these packages are going to be installed. I have
> >tried "grep" when doing "apt-get -s >upgrade" and "apt-show-versions -u",
> >and thought of piping the output trough "dpkg -L", but my knowledge is
> too
> >limited for >this.
> something like this should work:
> for i in $(apt-show-versions -u|awk '{print $1}'); do dpkg -L $i;done
>
> The awk '{print $1}' outputs the first collumn. I don't rember what column
> apt-show-versions shows the package name, so you may need to change this.
>
> To sort the output do this instead:
>
> sort <(for i in $(apt-show-versions -u|awk '{print $1}'); do dpkg -L
> $i;done)
>
>
>
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- Previous message: Andy Streich: "Re: 500 million Linux laptops in next year"
- In reply to: Joe Smith: "Re: How to list all files that are going to be installed when doing "apt-get upgrade"?"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
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