Re: Sed advice needed
- From: Tyler Smith <tyler.smith@xxxxxxxxxxxxxx>
- Date: 31 May 2007 16:58:38 GMT
On 2007-05-31, Piers Kittel <debian@xxxxxxxxxx> wrote:
"181","1324.014027","111.111.111.111","111.111.111.111","RTP","Payload t
ype=ITU-T H.261, SSRC=2008229573, Seq=54520, Time=1725612773, Mark"
"185","1324.078941","111.111.111.111","111.111.111.111","RTP","Payload t
ype=ITU-T H.261, SSRC=2008229573, Seq=54521, Time=1725616276"
I need to convert the above to the below:
"181","1324.014027","111.111.111.111","111.111.111.111","RTP","54520"
"185","1324.078941","111.111.111.111","111.111.111.111","RTP","54521"
What's the best way to do this? I've been reading the man pages of
sed, cut and awk but I can't quite figure out how to do this. Any
ideas?
If I understand what you want, you need the fields 1-5 and 8 from a
comma-delimited record. At least, that's what cut will see - the
quotes around Payload...Mark will get ignored if you tell cut to use a
, as delimiter:
cut -d, -f1,2,3,4,5,8
Then you just need to get rid of the Seq= line, which sed will do
with:
sed s/Seq=//g
So put them together:
cut -d, -f1,2,3,4,5,8 input.file | sed s/Seq=//g
That looks almost right. I'm missing the quotes around the last field.
Two more sed commands fix this:
cut -d, -f1,2,3,4,5,8 input.file |
sed -e s/Seq=//g -e 's/, /,"/g' -e 's/$/"/g'
That seems to do the job with your example text.
HTH,
Tyler
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