Re: quick script question
- From: "Mikkel L. Ellertson" <mikkel@xxxxxxxxxxxxxxxx>
- Date: Wed, 31 May 2006 13:20:16 -0500
M E Fieu wrote:
Hi.. Need to ask you a simple script question, I used the date command to get the yesterday webFor thing like this, I like to use something like:
log file using the following command echo ex`date -d yesterday +%y%m%d.log` in Linux. I want to
create a simple script to cat /home/IT/ex060530.log > kr.log using the following script but it is
not working. May I know how do I put the output of echo ex`date -d yesterday +%y%m%d.log into cat
/home/IT/xxxx > kr.log ?
[root@w2 krweblog3]# echo ex`date -d yesterday +%y%m%d.log`
ex060530.log
[root@w2 krweblog3]# vi krweblog.sh
#!/bin/sh
#
KRWEBLOG3= echo ex`date -d yesterday +%y%m%d.log`
cat /home/IT/$KRWEBLOG3 > kr.log
KRWEBLOG=$(date -d yesterday +ex%y%m%d.log)
cat /home/IT/$KRWEBLOG3 > kr.log
KRWEBLOG will have the value of ex060530.log if I ran it now on my
system. Enclosing a command inside $() returns the output of the
command. You could also use:
KRWEBLOG=`date -d yesterday +ex%y%m%d.log`
but I find the $() format easyer to read.
Mikkel
--
Do not meddle in the affairs of dragons,
for thou art crunchy and taste good with Ketchup!
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- quick script question
- From: M E Fieu
- quick script question
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