Re: Sort files by filename

On 7/31/07, Mark Haney <mhaney@xxxxxxxxxxxxxxxx> wrote:
Rodolfo Alcazar Portillo wrote:
Am Dienstag, den 31.07.2007, 11:00 -0400 schrieb Miner, Jonathan W (CSC)
(US SSA):
-----Original Message-----
From: fedora-list-bounces@xxxxxxxxxx on behalf of Mark Haney
Sent: Tue 07/31/2007 10:52 AM
To: For users of Fedora
Cc:
Subject: Sort files by filename

This is really a general linux question. I have a series of files in a
format like this:

XXXX20070515_112011_942_10.bz2
XXXX20070515_112011_942_12.bz2 etc,

and I am trying to find a way to do 2 things, one, sort these files in
order, and then once in order, find the files that are numerically
missing based on the last 2 numbers in the file name. So if I have (as
above I want to know that file XXXX20070515_112011_942_11.bz2 is
missing. Can someone get me started on this, I'm stumped.

Just an example tip which simply works with a counter, hope helps you.

a) Do you really need the sorting stuff? I didnt mess with that.

b) the counter:

[rodolfoap] /home/rodolfoap > for n in $(seq 10 40); do touch XXXX20070515_112011_942_${n}.bz2; done
[rodolfoap] /home/rodolfoap > rm XXXX20070515_112011_942_11.bz2
[rodolfoap] /home/rodolfoap > rm XXXX20070515_112011_942_22.bz2
[rodolfoap] /home/rodolfoap > rm XXXX20070515_112011_942_33.bz2
[rodolfoap] /home/rodolfoap > for n in $(seq 10 40); do if [ ! -e *_${n}.bz2 ]; then echo NOT FOUND: $n; fi; done
NOT FOUND: 11
NOT FOUND: 22
NOT FOUND: 33
[rodolfoap] /home/rodolfoap >

Good luck.

I think this would probably work except I really need to know which ones
are out of sequence as is, changing the filename would eliminate that
capability and the missing files are the ones I need. See, I'm
receiving the files from a separate server and they are sent to me in
this format. I need to know which ones I /don't/ receive so I know
which ones I need to have resent. Make sense?


Is there a reason why rsync cannot be used for this?


Mark Haney
Sr. Systems Administrator
ERC Broadband
(828) 350-2415

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