Re: bash question

On 10/31/07, Dario Lesca <d.lesca@xxxxxxxxxx> wrote:
In this shell script:

#!/bin/bash
i=0

printf "a a a\nb b b\nc c c\n" |
while read x
do
i=$[i+1]
echo "$x: ($i)"
done

echo $i

with this output:

a a a: (1)
b b b: (2)
c c c: (3)
0

How to I can get the value (3) for $i out of the while loop?

Many thanks

--
Dario Lesca <d.lesca@xxxxxxxxxx>

Is there a reason for using while instead of for?

for x in $(ls dir/)
do
.....
done

Jacques B.

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