Re: Bash: (foo==0)?foo=1:foo=0 valid?
- From: Marko Vojinovic <vvmarko@xxxxxxxxx>
- Date: Sat, 2 Jul 2011 19:01:09 +0100
On Saturday 02 July 2011 18:50:46 Joe Zeff wrote:
On 07/02/2011 10:45 AM, Daniel B. Thurman wrote:
I seem to forget my shell programming
but is the following statement valid?
($foo==0)?foo=1:foo=0
I thought it was called the tristate conditional
operator but in any case I could not find it in
google.
I don't know if it's allowed in bash, or any other shell. I do know,
however, that it's a valid construct in C.
With a small detail that the "$" in "$foo" is not actually a valid C construct
itself, right?
Or were you looking at the subject line, where the code doesn't have the "$"?
;-)
Best, :-)
Marko
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