Re: Bash: (foo==0)?foo=1:foo=0 valid?
- From: Joe Zeff <joe@xxxxxxx>
- Date: Sat, 02 Jul 2011 11:08:56 -0700
On 07/02/2011 11:01 AM, Marko Vojinovic wrote:
With a small detail that the "$" in "$foo" is not actually a valid C construct
itself, right?
Or were you looking at the subject line, where the code doesn't have the "$"?
The trinary operator itself is a valid C construct, even though the
example given wouldn't work. (Thanx for pointing out the error; it's
been way, way too long since I actually did any programming and didn't
notice it.)
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