Re: Apache vulnerability?
- From: Paul Allen Newell <pnewell@xxxxxxxxxx>
- Date: Tue, 01 Nov 2011 18:08:12 -0700
On 11/1/2011 5:42 PM, Alex wrote:
Thanks. If you bear with a couple "hopefully-not-too-naive" questions ...Yes, that's correct. You don't need to include the destination if you
I seems to me that you are saying the actions you wish to stop are from
"s<offending_ip>" using "-p tcp" ... why the need to specify the
destination of "-d<my_ip>" (since if this iptables rule is called, it
must have reached me regardless of my_ip) and "--dport 80" (would there
be any destination port that I would allow such action from this
offending_ip to occur on?).
only have one IP address on that host.
I am seeing in the default F14 iptables:Yes, that's a good approach too. If you are editing the existing
-A INPUT -p tcp -m state --state NEW -m tcp --dport 22 -j ACCEPT
This looks to me like tcp on dport 22 is allowed and there I would think
that the minimal change would be to insert a rule before this which says
"anything from offending_ip via tcp should be rejected".
I'm still trying to get comfortable with iptables and, even though there
is alot of stuff out there, I'm still working to get the necessary
critical mass of understanding so it all falls into place. This thread
looked like a good chance to see if I'm closer to understanding.
iptables config script from /etc/sysconfig/iptables, then that's
exactly what you would do. Something like this should work:
# Firewall configuration written by system-config-firewall
# Manual customization of this file is not recommended.
:INPUT ACCEPT [0:0]
:FORWARD ACCEPT [0:0]
:OUTPUT ACCEPT [0:0]
-A INPUT -m state --state ESTABLISHED,RELATED -j ACCEPT
-A INPUT -p icmp -j ACCEPT
-A INPUT -i lo -j ACCEPT
-A INPUT -m state --state NEW -m tcp -p tcp --dport 80 -j DROP -s
-A INPUT -m state --state NEW -m tcp -p tcp --dport 25 -j ACCEPT
-A INPUT -m state --state NEW -m tcp -p tcp --dport 80 -j ACCEPT
-A INPUT -m state --state NEW -m tcp -p tcp --dport 443 -j ACCEPT
-A INPUT -m state --state NEW -m tcp -p tcp --dport 22 -j ACCEPT
the "<offending_ip/range>" might be something like 18.104.22.168/24 to block
the entire 256 addresses on that network.
Thanks ... it does help to get a confirm that my understanding your
example is at least in the general right direction.
Just to check to make sure I got the last bit of info right ...
In your particular example of what appears to be China Telecom, are you
assuming that they are using the ip 22.214.171.124/24 and that translates to
I have a LAN which assumes router connecting to outside world is
192.168.1.1 and my network is 192.168.2.* (wireless only engaged when
necessary for both 192.168.1.1 and one Linksys at 192.168.2.2). To me,
this means that I "only have one IP address on that host" per your
email. If I am correct, I don't need to worry about a generalized
192.168.2.0/24 rule on each machine to prevent something I don't know about.
The addition of 25, 80, and 443 ports are your suggestions for what to
allow as opposed to manditories (everything is working nicely on my
system with the default and the only other port access I need to do is
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- Re: Apache vulnerability?
- From: Alex
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