Re: div64.h:do_div() bug
From: Matti Aarnio (matti.aarnio_at_zmailer.org)
Date: 09/30/03
- Previous message: John Bradford: "Re: bk2svn repo updatedness?"
- In reply to: Matti Aarnio: "Re: div64.h:do_div() bug"
- Next in thread: Andreas Schwab: "Re: div64.h:do_div() bug"
- Reply: Andreas Schwab: "Re: div64.h:do_div() bug"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
Date: Tue, 30 Sep 2003 14:28:30 +0300 To: Rogier Wolff <Swen-Trap1@BitWizard.nl>, Artur Klauser <Artur.Klauser@computer.org>, linux-kernel@vger.kernel.org
On Tue, Sep 30, 2003 at 01:14:38PM +0300, Matti Aarnio wrote:
> On Tue, Sep 30, 2003 at 11:52:29AM +0200, Rogier Wolff wrote:
> > On Mon, Sep 29, 2003 at 03:25:19PM +0200, Artur Klauser wrote:
> > > I've found that a bug in asm-arm/div64.h:do_div() is preventing correct
> > > conversion of timestamps in smbfs (and probably ntfs as well) from NT to
> >
> > Nope.
>
> Nope yourself.
>
> > > if (in.n64 != out.n64) {
> > > printf("FAILURE: asm/div64.h:do_div() is broken for 64-bit dividends\n");
> >
> > do_div should be/is documented as not doing 64 bit dividents. It does
> > 64/32 -> 32 divides, IIRC...
>
> 64/32 -> 64,32
>
> The REMAINDER is 32 bit value.
Non-native english speaker makes the mistake.. MODULUS is 32 bits as is
DIVISOR, REMAINDER is 64 bit, as is DIVIDEND.
That is:
DIVIDEND / DIVISOR -> REMAINDER , MODULUS
and
REMAINDER * DIVISOR + MODULUS = DIVIDEND
> > Roger.
/Matti Aarnio
-
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to majordomo@vger.kernel.org
More majordomo info at http://vger.kernel.org/majordomo-info.html
Please read the FAQ at http://www.tux.org/lkml/
- Previous message: John Bradford: "Re: bk2svn repo updatedness?"
- In reply to: Matti Aarnio: "Re: div64.h:do_div() bug"
- Next in thread: Andreas Schwab: "Re: div64.h:do_div() bug"
- Reply: Andreas Schwab: "Re: div64.h:do_div() bug"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
Relevant Pages
|
|
