Re: [2.4.28-rc1] process stuck in release_task() call
From: Andrey Melnikoff (temnota+news_at_kmv.ru)
Date: 11/11/04
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Date: Thu, 11 Nov 2004 16:37:31 +0300 To: Willy Tarreau <willy@w.ods.org>, linux-kernel@vger.kernel.org
Hello Willy Tarreau!
In article <20041111083312.GE783@alpha.home.local> you wrote:
> > > >>EIP; c012073d <release_task+1fd/230> <=====
> (...)
> > > c0120540 <release_task>:
> > > c0120540: 55 push %ebp
> > > ....
> > > c0120736: 89 d8 mov %ebx,%eax
> > > c0120738: e8 73 dd 01 00 call c013e4b0 <free_pages> <= here
> >
> > is this release_task+1fd? Can you send me the full disassemble of release_task?
> Yes it is because the next instruction after call will be at c0120738+5 =
> c012073d = release_task+1fd. (the return address on the stack is the
> address of the next instruction after the call).
> > It can't be blocked here, its a "call" instruction.
> Seems rather strange indeed ! Perhaps this is not the disassembled function
> of the *running* kernel ?
This is also strange for me. Stack trace should point into __free_pages_ok()
address space. Only this function work with lock's.
> it would be good to disassemble vmlinux and ensure that it is exactly
> the one currently running.
This is code from vmlinux-2.4.28-rc1.
> I too have already lost lots of time searching a wrong bug because I
> disassembled the wrong kernel, so I'm certain it can happen even when
> we're very careful :-(
[skipp]
PS: Please, keep CC: to me.
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- Previous message: Willy Tarreau: "[SECURITY] iSEC advisory about binfmt_elf"
- In reply to: Willy Tarreau: "Re: [2.4.28-rc1] process stuck in release_task() call"
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