RE: Print the first column of a file

amead_at_aicpa.org
Date: 07/29/03

  • Next message: John McKinney: "Re: List has died!" 
    To: redhat-list@redhat.com
Date: Tue, 29 Jul 2003 15:49:57 -0400

    Also, 'cut' is made for this sort of thing...
    -----Original Message-----
    From: redhat-list-admin@redhat.com [mailto:redhat-list-admin@redhat.com]

    Sent: Tuesday, July 29, 2003 1:52 PM
    To: redhat-list@redhat.com
    Subject: Re: Print the first column of a file

    Am Dienstag, 29. Juli 2003 15:58 schrieb Jason Dixon:
    > On Tue, 2003-07-29 at 10:07, Reuben D. Budiardja wrote:
    > > Hello,
    > > What command would I use to print just the first column of a file?
    > > For example, the httpd (apache) access_log. The first column
    > > contains the IP address. How can I just output that, so that I can
    > > then pass it to "uniq" to get the uniques IP addresses that
    > > requested a page from my server?
    > > Like:
    > >
    > > $> <command> | uniq
    > >
    > > Does this use something like 'sed' or 'gawk'? I need to learn how to

    > > use those anyways :)
    >
    > Yes.
    >
    > $ cat /var/log/httpd/access_log | awk '{print $1}' | sort | uniq

    ..useless use of cat:
             awk '{print $1}' /var/log/httpd/access_log | sort | uniq
    is enough.

    Christian Paul 

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