Re: Format Output of bash into columns

From: Anthony E. Greene (tony_at_greene-family.org)
Date: 11/27/04

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    Date: Fri, 26 Nov 2004 19:27:09 -0500
To: General Red Hat Linux discussion list <redhat-list@redhat.com>

    On 26-Nov-2004/17:37 -0600, Mike Vanecek <rh_list@mm-vanecek.cc> wrote:
    >I have looked through my books and googled ... Tried serveral things without
    >success ...
    >
    >I would like to run the output of a bash command that produces 1 field per
    >line output through sort and then output in 3 columns. I have looked at
    >printf, fmt, column, and so on.
    >
    >For example,
    >
    >rpm -qa | sort 2>&1 | column -c 2
    >
    >rpm -qa | sort | column -c 2
    >
    >Or say I have a file with a list of sorted names, for example,
    >[admin@www admin]$ rpm -qa | sort -o rpm.txt
    >
    >Then I want to output the file with
    >
    >column -c 2 rpm.txt
    >

    #!/usr/bin/perl
    #
    # Format STDIN into three tab-delimited columns
    #
    $colnum = 1;
    while ($line = <STDIN>) {
      chomp $line;
      if ($colnum < 3) {
        print "$line "; # The whitespace is a tab character.
      } else {
        print "$line\n";
      }
    }

    You could get fancy using perl's formatting features, but this quick$
    dirty should work for lines that are all of similar length, or for input
    in an application that easily parses tab-delimited data.

    Tony 

    -- 
Anthony E. Greene <mailto:Anthony%20E.%20Greene%20%3Ctony@greene-family.org%3E>
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