RE: Quick question on awk usage



-----Original Message-----
From: redhat-list-bounces@xxxxxxxxxx
[mailto:redhat-list-bounces@xxxxxxxxxx] On Behalf Of Bliss, Aaron
Sent: Tuesday, June 27, 2006 11:03 AM
To: redhat-list@xxxxxxxxxx
Subject: RE: Quick question on awk usage

Sorry, $14 == 528, not $12 (looks like the email client
wrapped the line
also)

Aaron

Hi everyone, I have a quick question on using awk from the
command line; I have a tab delimited file, and would like to
know the syntax to print the entire line only when $12 ==
575; the syntax from the command line to print only $1 would
be cat security.log | awk '{print $1}' ; any ideas (grepping
for 578 won't be good enough since it's possible that
578 could appear somewhere else in the file) Thanks very much.

Aaron

Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 4
Security 263985 Sun Jun 25 15:54:02 2006 528
Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 4
Security 263985 Sun Jun 25 15:54:02 2006 575



I believe this should do it:

awk ' $14 == 575 {print $0}'

Michael

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