Re: [opensuse] [OT] How much power does a PC really consume?



Aaron Kulkis wrote:

RMS is just as statistical method, which is useful for making
sense of any time-variant function.

The square root of the square of power is just as much related
to power as the square root of the square of voltage is related
to voltage (NOT power).



Judging from this response and the one to Randall, I suspect it might be a good idea for you to review your EE texts. RMS is meaningless in the context of power. Sure you can do the calculation, but what does it get you? With current or voltage, RMS derives the equivalent DC value. Can you explain what you'd obtain by calculating RMS power?

--
Use OpenOffice.org <http://www.openoffice.org>
--
To unsubscribe, e-mail: opensuse+unsubscribe@xxxxxxxxxxxx
For additional commands, e-mail: opensuse+help@xxxxxxxxxxxx



Relevant Pages

  • Re: AC power measurement
    ... voltage and current will give the power dissipated. ... A simple way for mains powered devices is to measure the ... RMS current and multiply by the nominal/actual RMS voltage. ...
    (uk.comp.homebuilt)
  • Re: AC power measurement
    ... voltage and current will give the power dissipated. ... RMS current and multiply by the nominal/actual RMS voltage. ... Metrawatt analogue wattmeter using 'simple' analogue multiplier ...
    (uk.comp.homebuilt)
  • Re: Feedback for low frequency PWM regulator
    ... described in a thread called "RMS Approximation of PWM/Square wave". ... However, since the Vin is from batteries, the input voltage will be falling ... IRLR7843 for lower power applications and the IRF2804S for higher power ones. ... By regulating the rms voltage across the lamp, ...
    (sci.electronics.design)
  • Re: Feedback for low frequency PWM regulator
    ... described in a thread called "RMS Approximation of PWM/Square wave". ... However, since the Vin is from batteries, the input voltage will be falling ... IRLR7843 for lower power applications and the IRF2804S for higher power ones. ... By regulating the rms voltage across the lamp, ...
    (sci.electronics.design)
  • Re: Question about calculating power factor...
    ... Let's say I start with 120VAC and 2A, both RMS. ... The top one is voltage, the middle one is amps, and the bottom one is V*A ... Power from this measurement. ... Apparent power is then = Watts / cos(phi) ...
    (sci.electronics.design)