Re: Scripting

Calab wrote:
#!/bin/bash
for i in $(command)
do
j=$(echo "$i" | cut -f4)
k=$(echo "$i" | cut -f3)
[ "$j" = "busy" ] && syscheck "$k"
done
#

where "command" gives your table, "cut" assumes tabs are the column delimiters. - man cut

For some reason, $i does not contain the complete line. It only contains one column...

Tried a very simple run and you can see that each line output by the ls -l command is split up.

bash-2.05$ for i in $(ls -l) ; do(echo $i ) ; done

try for i in "$(ls -l)"

--
c.e@xxxx
.

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