Re: Scripting


"Chris Elvidge" <chris.elvidge@xxxxxxxxxxxxxxxx> wrote in message
news:c3om45-1e1.ln1@xxxxxxxxxxxxxxxxxxx
Calab wrote:
#!/bin/bash
for i in $(command)
do
j=$(echo "$i" | cut -f4)
k=$(echo "$i" | cut -f3)
[ "$j" = "busy" ] && syscheck "$k"
done
#

where "command" gives your table, "cut" assumes tabs are the column
delimiters. - man cut

For some reason, $i does not contain the complete line. It only contains
one column...

Tried a very simple run and you can see that each line output by the
ls -l command is split up.

bash-2.05$ for i in $(ls -l) ; do(echo $i ) ; done

try for i in "$(ls -l)"

Nope... that returns ALL of the ls output as a single line, instead of an
instance of $i for each line.


.