Re: Scripting

Chris Elvidge <chris.elvidge@xxxxxxxxxxxxxxxx> writes:

Calab wrote:
"Chris Elvidge" <chris.elvidge@xxxxxxxxxxxxxxxx> wrote in message
news:c3om45-1e1.ln1@xxxxxxxxxxxxxxxxxxx
Calab wrote:
#!/bin/bash
for i in $(command)
do
j=$(echo "$i" | cut -f4)
k=$(echo "$i" | cut -f3)
[ "$j" = "busy" ] && syscheck "$k"
done
#

where "command" gives your table, "cut" assumes tabs are the
column delimiters. - man cut
For some reason, $i does not contain the complete line. It only
contains one column...

Tried a very simple run and you can see that each line output by
the ls -l command is split up.

bash-2.05$ for i in $(ls -l) ; do(echo $i ) ; done
try for i in "$(ls -l)"

Nope... that returns ALL of the ls output as a single line, instead
of an instance of $i for each line.


Did you try quotes round $i too?

Watching this unfold, I have one question : did this solution you gave
work for you?
.