Help needed in solving C-errors in Linux (gcc)

From: Dominic Grosleau (dominic_at_localhost.localdomain)
Date: 07/25/03 

Date: Thu, 24 Jul 2003 19:14:44 -0400

When i tried to compile this test driver for an actual conversion library
i'm trying to make I got the following messages from gcc.

                                        /*problems reported*/

gcc convertlib.c main.c -ansi -pedantic

main.c:21:22: warning: character constant too long
main.c:22:41: warning: multi-character character constant
main.c: In function `convert':
main.c:22: warning: comparison is always false due to limited range of data type
main.c:22:61: warning: multi-character character constant
main.c:22: warning: comparison is always false due to limited range of data type

What i really want is for the convert() function in main() to behave correctly to
the way i'm passing its parameter.

I'm guessing i screwed up somewhere in the convertlib.h definition or in
the main.c convert() implementation...

Please help !!!

                                /* main.c */

#include <stdio.h>
#include "convertlib.h"

int main()
{
        int result = 0;

        result = convert(12, "imperial", "inch", "feet");

        printf("\n12 imperial inches = %d feet\n", result);

        return 0;
}

int convert(int unit, const char *sys, const char *initial, const char *final)
{
        int success = 0;

        switch(*sys)
        {
                case 'imperial':
                        if (*initial == 'inch' && *final == 'feet')
                                success = conv_inch2feet(unit);
                default:
                        success = 1;
        };

        return success;
}

                                /*convertlib.h*/
                                

#define FOOT 12 /* # of inches in a foot
int conv_inch2feet(int inch);
int convert(int unit, const char *,const char *,const char *);

                                /*convertlib.c*/
int conv_inch2feet(int inch)
{
        feet = inch / FOOT;

        return feet;
}

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