Re: compute lat/long given lat/long plus distance and bearing

"Eric" <Scorpus@xxxxxxxxxxxxxx> wrote in message
news:Q5ydnYdFzYcp9v3VnZ2dnUVZ_jmdnZ2d@xxxxxxxxxxx
Has anyone got a formula that:
given a lat/long starting point plus a distance and bearing
will output the new lat/long position?

I found this but it doesnt seem to work right

double curLat=40.12345;
double curLong=-122.12345;
double bearing=90; // east
double dist=1609.344; // 1 mile in meters

d_lat = asin(sin(curLat)* cos(dist)+ cos(curLat)*
sin(dist)*cos(bearing)); d_lon =
atan2(sin(bearing)*sin(dist)*cos(curLat),
cos(dist)-sin(altitude)*sin(curLat)); d_long = fmod( curLong -
d_lon + pi, 2*pi )- pi;

printf("new coordinates: %lg x %lg\n", d_lat, d_long);

my results look like this:
new coordinates: -0.384715 x -6.1364

Your trig functions are probably looking for angles in
radians, not degrees.

You'll have to convert your distance to angular measure,
most likely by dividing it by the radius of the Earth.

What is that undeclared altitude variable in the atan2
calculation? I suspect it should be d_lat.
.

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