Re: logical OR in bash

Yanb <Yanb@xxxxxxxxxxxxxxxx> writes:

Hi, a simple question, I'm new to bash (and linux completely:-)

How do I compare more things in bash?

this works fine:
---
echo "Are you sure? Type YES and press ENTER."
read LINE
if [ "$LINE" != "yes" ]; then
exit 1
fi
echo "great"
---

but what if I want to compare to "YES". I tried whatever I know from php or C, but anything like
if [ (("$LINE" != "yes") && ("$LINE" != "YES")) ]; then

does not work. I know I sloudh convert it to upper case for best result, whatever, but I need to know
how to make more conditions in single if :-)

So how to make it right? ;-) Thank you in advance.

Shell comparisons are done best with the case statement since it supports
regular expressions.

Example:

case $LINE in
YES | yes)
echo "matched"
;;
* )
echo "no match"
;;
esac

Another possibility:

[yY][eE][sS]


.

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