grep for a nuimber with a decimal point - please help

From: noob (noob_at_no.noo)
Date: 03/20/04

  • Next message: johnny bobby bee: "Re: directory to install progams?" 
    Date: Fri, 19 Mar 2004 20:31:36 -0700

    hi, yes I know I am an idiot ; )

    I am having a problem searching for the string "8.0" because awk assumes the
    "." is a wildcard so it would return a line like this from sourcefile:

    12345678, username, 01/02/2004, 6.2, Colorado

    because there is an 8 with a 0 somewhere after it on the line.

    I only want it to return line with 8.0 like this:

    12345678, username, 01/02/2004, 8.0

    this is what I am trying, where $FF = 8.0

    awk '/ '$FF'/ {print$1,$2,$3,$4}' sourcefile

    and it returns any line that has an 8 somewhere before a 0

    additionally - can I have grep only search field 4 for my string?

  • Next message: johnny bobby bee: "Re: directory to install progams?"

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